Family Mathematics Problem Solving
Sponsored by
The Somerville Mathematics Fund
The Family Mathematics problems are written for adults and children to work on together. They are not meant as another homework to be turned in to your child’s teacher, instead it is an opportunity for you to work together to solve a mathematical problem. This Month’s Family Mathematics Problems keeps up our upcoming election. We hope you will enjoy working together to solve these problems. The solutions were printed in the Somerville Journal. Enjoy.

The Somerville Mathematics Fund was founded in 2000 to celebrate and encourage mathematics achievement in the city of Somerville. We offer scholarships to students and grants to teachers.
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From June 2004
 Solutions
 
Grades 4, 5,
Grade 6
Grades 7 and 8



Family Mathematics Problem Solving: Grades 4 and 5

Senator John Kerry’s Speaking Tour
Senator Kerry needs to visit Somerville, Malden and Newton and then return to his home in Boston. For this activity let’s use S for Somerville, M for Malden, N for Newton and B for Boston. Start by listing all the ways he can visit those towns: S__M__N, S__N__M, M__S__N, M__N__S, N__S__M, N__M__S. There are 6 different trips he can take.
Now we need to remember that he must begin and end in Boston; and we need to go back and figure out how long each of these trips are in miles. S__M__N is reallly B__S__M__N__B and if we write the distance between each city on the lines, we can figure out how long each trip is: B 3.3 S 4.6 M 16.7 N 9.6 B, adding 3.3, 4.6, 16.7, 9.6 is 34.2 miles.
You should have found that: B__S__M__N__B is 34.2 miles, B__S__N__M__B is 34.5 miles, B__M__S__N__B is 28.7 miles, B__M__N__S__B is 34.5 miles, B__N__S__M__B is 28.7 miles, and B_N__M__S__B is 34.2 miles. You should have found that Kerry’s going from his home in Boston to Malden then Somerville and then Newton before returning home (or the reverse order) is the shortest.



Family Mathematics Problem Solving: Grade 6 Grades 7 and 8

 

Senator Kerry’s Campaign Tour of the Country


If you look at the 4th and 5th grade problem, you would see that John Kerry needed to visit 3 places instead of 49 cities. One way of thinking about the answer to that problem is to say, Kerry has 3 ways to choose the first city to visit. Once he has made that choice, he has 2 ways to decide where to go next and finally 1 way to choose the last city to go to. To find the total number of ways, you multiply 3 X 2 X 1 which equals 6.
Now we apply that technique to this problem, there are 49 ways to choose the first city, 48 ways to choose the second city, 47 ways to choose the third city, and so forth until there is just 1 way to choose the forty-ninth city. Then you need to multiply all forty-nine numbers to get the answer: 49 X 48 X 47 X 46 X 45 X ... X 4 X 3 X 2 X 1. If you try to do this on a calculator, you will need a scientific calculator because the answer has 63 digits! It is written 49! and called 49 factorial. It is approximately equal to 608,281,864,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000 ways.
The second question was how long would it take to write out all these different orders, taking one second to write each one. If you convert 608,281,864,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000 seconds into years by dividing by 60, 60, 24 and 365.25, you get a 56 digit answer: 19,275,289,120,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000 years. Needless to say, you will not finish this in your lifetime and definitely not before Kerry needs to plan his campaign tour!


Other Problem Solving Sources:
http://mathforum.org/pow/
http://www.figurethis.org/index40.htm
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