| Family
Mathematics Problem Solving: Grades 4,
5, 6, 7, 8 |
The Twelve Days of Christmas
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(1) How much would my true love need to spend to buy me all of these
gifts according to these prices?
Listening to the song repeat and add items each time shows that we need
to buy 12 of the first gift at $135, 11 of the 2nd gift at $15, and so
to find the total cost:
(12 x $135) + (11 x $58) + (10 x $15) + (9 x $316) + (8 x $375) + (7 x
$150) + (6 x $3,500) + (5 x $41.21) + (4 x $4,019.24) + (3 x $3,770.62)
+(2 x $1,614.60) + (1 x $1,749.15) = $1,620 + $638 + $150 + $ 2,844 + $3,000
+ $1,050 + $21,000 + $206.05 + $16,076.96 + $11,311.86 + $3,229.20 + $1,749.15
= $62,875.22 |
(2) If I was overwhelmed by the space that the number of gifts took up
in my home and decided to return them, one each day starting the day after
Christmas, on which date would I return the last gift?
Again, the first gift is given twelve times, the 2nd eleven times, and
so the total number of gifts is:
(12 x 1) + (11 x 2) + (10 x 3) + (9 x 4) + (8 x 5) + (7 x 6) + (6 x 7)
+ (5 x 8) + (4 x 9) + (3 x 10) + (2 x 11) + (1 x 12) = 12 + 22 + 30 + 36
+ 40 + 42 + 42 + 40 + 36 + 30 + 22 + 12 = 364 gifts. If I returned one
gift per day, starting on the day after Christmas, I would finish on Christmas
day 2003 (since 2003 is not a leap year). |
(3) What is the percent inflation since 1985 for just one of each gift?
The cost of one of each gift is $15,743.82. That is an increase of $3,463.82
over the cost of $12,280 in 1985. To find the percent increase: divide
3,463.82 by 12,280 and multiply your quotient by 100. This gives an approximately
28% increase.
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